Random variables are independent iff their joint distribution is the product measure. #
There are several possible measurability assumptions:
- The map
ω ↦ (Xᵢ(ω))ᵢis measurable. - For all
i, the mapω ↦ Xᵢ(ω)is measurable. - The map
ω ↦ (Xᵢ(ω))ᵢis almost everywhere measurable. - For all
i, the mapω ↦ Xᵢ(ω)is almost everywhere measurable. Although the first two options are equivalent, the last two are not if the index set is not countable. Therefore we first prove the third caseiIndepFun_iff_map_fun_eq_infinitePi_map₀, then deduce the fourth case iniIndepFun_iff_map_fun_eq_infinitePi_map₀'(assuming the index type is countable), and we prove the first case iniIndepFun_iff_map_fun_eq_infinitePi_map.
theorem
ProbabilityTheory.iIndepFun_iff_map_fun_eq_infinitePi_map₀
{ι : Type u_1}
{Ω : Type u_2}
{mΩ : MeasurableSpace Ω}
{μ : MeasureTheory.Measure Ω}
[MeasureTheory.IsProbabilityMeasure μ]
{𝓧 : ι → Type u_3}
{m𝓧 : (i : ι) → MeasurableSpace (𝓧 i)}
{X : (i : ι) → Ω → 𝓧 i}
(mX : AEMeasurable (fun (ω : Ω) (i : ι) => X i ω) μ)
:
iIndepFun X μ ↔ MeasureTheory.Measure.map (fun (ω : Ω) (i : ι) => X i ω) μ = MeasureTheory.Measure.infinitePi fun (i : ι) => MeasureTheory.Measure.map (X i) μ
Random variables are independent iff their joint distribution is the product measure. This
is a version where the random variable ω ↦ (Xᵢ(ω))ᵢ is almost everywhere measurable.
See iIndepFun_iff_map_fun_eq_infinitePi_map₀' for a version which only assumes that
each Xᵢ is almost everywhere measurable and that ι is countable.
theorem
ProbabilityTheory.iIndepFun_iff_map_fun_eq_infinitePi_map₀'
{ι : Type u_1}
{Ω : Type u_2}
{mΩ : MeasurableSpace Ω}
{μ : MeasureTheory.Measure Ω}
[MeasureTheory.IsProbabilityMeasure μ]
{𝓧 : ι → Type u_3}
{m𝓧 : (i : ι) → MeasurableSpace (𝓧 i)}
{X : (i : ι) → Ω → 𝓧 i}
[Countable ι]
(mX : ∀ (i : ι), AEMeasurable (X i) μ)
:
iIndepFun X μ ↔ MeasureTheory.Measure.map (fun (ω : Ω) (i : ι) => X i ω) μ = MeasureTheory.Measure.infinitePi fun (i : ι) => MeasureTheory.Measure.map (X i) μ
Random variables are independent iff their joint distribution is the product measure. This is
an AEMeasurable version of iIndepFun_iff_map_fun_eq_infinitePi_map, which is why it requires
ι to be countable.
theorem
ProbabilityTheory.iIndepFun_iff_map_fun_eq_infinitePi_map
{ι : Type u_1}
{Ω : Type u_2}
{mΩ : MeasurableSpace Ω}
{μ : MeasureTheory.Measure Ω}
[MeasureTheory.IsProbabilityMeasure μ]
{𝓧 : ι → Type u_3}
{m𝓧 : (i : ι) → MeasurableSpace (𝓧 i)}
{X : (i : ι) → Ω → 𝓧 i}
(mX : ∀ (i : ι), Measurable (X i))
:
iIndepFun X μ ↔ MeasureTheory.Measure.map (fun (ω : Ω) (i : ι) => X i ω) μ = MeasureTheory.Measure.infinitePi fun (i : ι) => MeasureTheory.Measure.map (X i) μ
Random variables are independent iff their joint distribution is the product measure.